5t^2+280t=11760

Solution for 5t^2+280t=11760 equation:

5t^2+280t=11760

We move all terms to the left:

5t^2+280t-(11760)=0

a = 5; b = 280; c = -11760;
Δ = b2-4ac
Δ = 2802-4·5·(-11760)
Δ = 313600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{313600}=560$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-560}{2*5}=\frac{-840}{10}
=-84
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+560}{2*5}=\frac{280}{10}
=28
$